From 1d5f440ba7f52aab4b661b459a77558fe2ae7256 Mon Sep 17 00:00:00 2001
From: Luis Rodrigues <sanctus.hck@gmail.com>
Date: Wed, 12 Feb 2025 19:24:19 +0000
Subject: [PATCH] exercicio 1502 resolvido em python

---
 .../python/1502.py                            | 28 +++++++++++++++++++
 1 file changed, 28 insertions(+)
 create mode 100644 1502-can_make_arithmetic_progression_from_sequence/python/1502.py

diff --git a/1502-can_make_arithmetic_progression_from_sequence/python/1502.py b/1502-can_make_arithmetic_progression_from_sequence/python/1502.py
new file mode 100644
index 0000000..6a1e57b
--- /dev/null
+++ b/1502-can_make_arithmetic_progression_from_sequence/python/1502.py
@@ -0,0 +1,28 @@
+# 1502. Can Make Arithmetic Progression From Sequence
+#
+# A sequence of numbers is called an arithmetic progression if the difference
+# between any two consecutive elements is the same.
+#
+# Given an array of numbers arr, return true if the array can be rearranged to
+# form an arithmetic progression. Otherwise, return false.
+#
+
+# usar o metodo sort() para ordenar o vector
+# se o vector tiver tamanho 2, retorna True (só temos a diferença entre dois
+# numeros)
+# calculamos a diferença entre os dois primeiros numeros, e procuramos nos
+# restantes pares de numeros consecutivos se a diferença é igual, se não for
+# retornamos False
+# se chegarmos ao fim do vector e se mantiver a diferença, então o vector
+# tem uma sequencia de progressão aritmetica
+
+
+def canMakeArithmeticProgression(array: list[int]) -> bool:
+    array.sort()
+    if len(array) == 2:
+        return True
+    diff: int = array[1] - array[0]
+    for index in range(1, len(array)):
+        if diff != (array[index] - array[index - 1]):
+            return False
+    return True